Wrap std::vector of std::vectors, C++ SWIG Python

Question

I want to wrap a C++ vector of vectors to Python code by using SWIG.

Is it possible to wrap this type of vector of vectors?

std::vector<std::vector<MyClass*>>;

In the interface file MyApplication.i I added these lines:

%include "std_vector.i"
%{ 
#include <vector> 
%} 

namespace std {
   %template(VectorOfStructVector) vector<vector<MyClass*>>;
}

But, I'm getting an Error when SWIG is executed. I'm able to wrap this type (using reference to the vector):

 std::vector<std::vector<MyClass*>*>;

But, it's not working properly, I cannot access the items. That's why I'm interested in this type (without the reference):

 std::vector<std::vector<MyClass*>>;

Any ideas?

If this really is C++ and not C++0x, please make sure you include a space between the closing angle brackets. eg `>>` should be `> >` — John Dibling, Sep 21 '10 at 15:47
Duplicate of http://stackoverflow.com/questions/3754922/how-to-wrap-a-c-vector-of-vector-with-swig ? — Lightness Races in Orbit, Jan 03 '11 at 04:32

score 4 · Accepted Answer · answered Sep 21 '10 at 15:47

4

Is it a C++ parsing issue?

 std::vector<std::vector<MyClass*> >;
 ---Important space---------------^

answered Sep 21 '10 at 15:47

Charles Beattie

Also this line was needed in the interface file: %template(VectorOfStructVector) vector >; – Javier Sep 21 '10 at 21:52
@Javier, another solution is to compile with "--std=c++0x" if you're using gcc. C++0x has fixed this problem. – Neil G Mar 10 '11 at 08:01

1 Answers1