Clojure: fully qualified name of a function

Question

In Clojure, is there a more elegant way of finding the fully qualified name of a function (known to have meta info) than

(defn fully-qualified-name [fn]
  (let [fn-meta (meta fn )
        fn-ns (ns-name (:ns fn-meta))
        ]
    (str fn-ns "/" (:name fn-meta))))

A run-time solution is required. Read-time and compile-time solutions are welcome.

Does it have to be in a function (rather than at compile time in a macro or the REPL)? — mikera, Sep 21 '10 at 15:30

score 11 · Accepted Answer · answered Sep 21 '10 at 16:56

11

(resolve 'foo) returns the Var named "foo", with its fully-qualified name.

answered Sep 21 '10 at 16:56

Stuart Sierra

score 5 · Answer 2 · answered Sep 21 '10 at 15:23

5

how about syntax-quoting ? it does auto-qualification. use ` instead of '

user=> `(inc)
(clojure.core/inc)
user=> `(fn)
(clojure.core/fn)

answered Sep 21 '10 at 15:23

Belun

Very elegant and useful at read-time. (str `inc) would be equivalent of fully-qualified-name. Any run-time solution? – chris Sep 21 '10 at 16:13
what do you plan on doing with the result ? – Belun Sep 21 '10 at 16:22
Not all functions have a fully-qualified-names (anonymous functions have not as partial....). That's a strange thing to lookup dynamically. – Nicolas Oury Sep 21 '10 at 16:34
@Nicolas I have modified the question to clarify that a solution for functions with fully qualified names is sufficient. – chris Sep 21 '10 at 21:13

score 2 · Answer 3 · answered Mar 05 '14 at 14:19

2

type gives a fully qualified name, regardless of meta info.

answered Mar 05 '14 at 14:19

score 1 · Answer 4 · answered Sep 21 '10 at 16:05

1

The output of .toString could get you started:

user=> (.toString map)
"clojure.core$map@11af7bb"

answered Sep 21 '10 at 16:05

Michael Kohl

1

also written (str map) to get the fully qualified name use (str `map) – Arthur Ulfeldt Sep 22 '10 at 17:54

4 Answers4