TypeError when creating file with python 3

Asked May 31 '16 at 10:07

Active May 31 '16 at 10:07

Viewed 39 times

I am simply trying to make a new file with python 3.4, but whenever I try it gives me a TypeError:

    >>> f = open("test.txt","w")
    Traceback (most recent call last):
      File "<pyshell#22>", line 1, in <module>
        f = open("test.txt","w")
    TypeError: an integer is required (got type str)

please help, I have tried so hard to fix this but it won't

(Sorry if it's something obvious, I'm kind of new to this)

asked May 31 '16 at 10:07

Dylan D.B

1

I'm guessing you have `from os import *`? – miradulo May 31 '16 at 10:08
3

99% chance you rebound `open` to something else. – TigerhawkT3 May 31 '16 at 10:08
4

This doesn't happen with the regular `open`, please give a [mcve]. – jonrsharpe May 31 '16 at 10:09
Taken out of context, this shouldn't happen. There's some voodoo we're not seeing here. – jDo May 31 '16 at 10:10
I have tested this on Python 3.4.4 and I don't get an error (although I expected one). You are in the interactive shell, right? Try to use the full path of where you want the file to be. – Matthias Schreiber May 31 '16 at 10:11
Don't worry i fixed it. For anyone who stumbles upon this though: – Dylan D.B Jun 01 '16 at 07:54
And thank you to every one to helping – Dylan D.B Jun 01 '16 at 07:54
I had "from os import *" and so it was trying to use os.open() instead of the regular, which requires an integer instead of 'r', 'w', or 'x' – Dylan D.B Jun 01 '16 at 07:56

TypeError when creating file with python 3

0 Answers0