How to get a node in a tree by its label in nltk python?

Question

I have a tree:

(S  
    (WH-QUERY Which)  
    (FLIGHT-NP   
        (FLIGHT-CNP  
            (FLIGHT-CNP (FLIGHT-N flight))  
            (FLIGHT-DEST to (CITY-NP (CITY-NAME Hue) (CITY-N city)))))  
    (FLIGHT-VP  
        (FLIGHT-V arrives)  
        (FLIGHT-TIME (P-TIME at) (TIME-MOD 20:00HR))))

I want to get a specific node by its label in nltk. For example, I have label "CITY-NAME", and I want to get the node (CITY-NAM Hue). How can I achieve this?

score 3 · Accepted Answer · answered Jun 14 '16 at 18:37

3

One way to do it is to walk the tree searching for nodes that match:

for subtree in tree.subtrees():
     if subtree.label() == 'CITY-NAME':
          print subtree.leaves()

answered Jun 14 '16 at 18:37

rmalouf

3,353
1
15
10

score 0 · Answer 2 · answered Jun 04 '16 at 07:15

0

Look at the _get_node method in the function.

http://www.nltk.org/_modules/nltk/tree.html

answered Jun 04 '16 at 07:15

aerin

20,607
28
102
140

`_get_node()` has been replaced with `label()`, and that tells you the label of a tree. It doesn't find a tree by its label. – rmalouf Jun 14 '16 at 18:33

How to get a node in a tree by its label in nltk python?

2 Answers2

Linked

Related