I need to get information from JSON in PHP

Question

Here is the result of: var_dump($response):

"is_claimed": false, "rating": 4.5, "mobile_url": "http://m.yelp.com/biz/filbert-steps-san-francisco?utm_campaign=yelp_api\u0026utm_medium=api_v2_business\u0026utm_source=NUQkLT4j4VnC6ZR7LI-VWA", "rating_img_url": "https://s3-media2.fl.yelpcdn.com/assets/2/www/img/99493c12711e/ico/stars/v1/stars_4_half.png", "review_count": 208

I want to get the rating value, I tried $response->rating but I got nothing.

That doesn't look like JSON to me - it should have `{}` curly braces wrapped around it. What do you get from `print_r(json_decode('{' . $response . '}'))`? — halfer, May 29 '16 at 12:59
If that's the result of dumping `$response`, could we see the source JSON please? And your code? — starbeamrainbowlabs, May 29 '16 at 13:01

score 1 · Accepted Answer · answered May 29 '16 at 13:02

You need to make this json first by using {} at two sides of the string. After decoding (json_decode) you will got an Array of Objects.

$json = '{"is_claimed": false, "rating": 4.5, "mobile_url": "http://m.yelp.com/biz/filbert-steps-san-francisco?utm_campaign=yelp_api\\u0026utm_medium=api_v2_business\\u0026utm_source=NUQkLT4j4VnC6ZR7LI-VWA", "rating_img_url": "https://s3-media2.fl.yelpcdn.com/assets/2/www/img/99493c12711e/ico/stars/v1/stars_4_half.png", "review_count": 208}';
$result = json_decode ($json);

echo $result->rating; // 4.5

Online Check, and let me know is it works for you or not.

I need to get information from JSON in PHP

1 Answers1