How to go another page when I press settings button on action bar?

Question

I face a problem when I try press the settings icon on action bar and go to settings page in my android project.

Here is the code:

public boolean onOptionsItemSelected(MenuItem item) {

        if(item.getItemId() == R.id.settings) {
            startActivity(new Intent(ProfileFragment.this, SettingsActivity.class));
        }

        return super.onOptionsItemSelected(item);
}

The error is in ProfileFragment.this, SettingsActivity.class line. There is no fatal error but there is a red line under the code.

How can I solve this?

Thanks for answers.

Pass context at startActivity(new Intent("context", SettingsActivity.class)); — J.D., May 27 '16 at 13:24

score 2 · Accepted Answer · edited May 27 '16 at 13:34

2

Use this

    public boolean onOptionsItemSelected(MenuItem item) {

        if(item.getItemId() == R.id.settings) {
            startActivity(new Intent(getContext(), SettingsActivity.class));
        }

        return super.onOptionsItemSelected(item);
    }

edited May 27 '16 at 13:34

Nongthonbam Tonthoi

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answered May 27 '16 at 13:25

Vishwesh Jainkuniya

2,821
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score 0 · Answer 2 · answered May 27 '16 at 13:30

0

Change this:

startActivity(new Intent(ProfileFragment.this, SettingsActivity.class));

to :

startActivity(new Intent(getActivity(), SettingsActivity.class));

answered May 27 '16 at 13:30

Nongthonbam Tonthoi

12,667
7
37
64

score 0 · Answer 3 · answered May 27 '16 at 13:31

Try This

 public boolean onOptionsItemSelected(MenuItem item) {

            if(item.getItemId() == R.id.settings) {
                startActivity(new Intent(getActivity().getApplicationContext(), SettingsActivity.class));
            }

            return super.onOptionsItemSelected(item);
    }

How to go another page when I press settings button on action bar?

3 Answers3