Array Spread Operator in Pure Function

Question

In Redux Tutorial, they have used array spread operator a lot for writing reducers(which have to be pure functions) . Go through the following script.

let a = {
  b : "ddff",
  c : "adxas"
}

let c = {
  b : "ssdds",
  c : "asdxasdsad"
}

let d = [];

d.push(a);
d.push(c);

console.log(d);

const pureFunc = (arr,b,c) => {
  return [...arr, { b , c}];
}

let n = pureFunc(d,"daaaa","sdadad");
console.log(n);
d[0].b = "Hello";
console.log(n)

Is the function "pureFunc" is a proper pure function. Mutations on array d are getting reflected in object n.

I’m not sure what your question is exactly. – Sebastian Simon May 20 '16 at 12:16 — Sebastian Simon, May 20 '16 at 12:16

score 2 · Accepted Answer · answered May 20 '16 at 12:17

Yes, pureFunc is pure. The mutation does not occur within pureFunc.

One of the most common and basic pure functions is the identity function:

let identity = x => x;

So, if we pass that an object, we'll get the same object back. We can modify it after the fact, but that doesn't make identity impure, because identity isn't doing the mutation.

Basically, pure functions only need to satisfy two requirements:

They always produce the same output given the same input
They do not cause side effects

Array Spread Operator in Pure Function

1 Answers1