var_dump output using foreach reference loop

Question

I am using a foreach loop with referencing, ie: foreach($elements as &$item)

Now when I use var_dump($elements); after the foreach(), the last element always has an & character prepended to it's variable-type (&string, &array, &boolean, etc).

Example output:

array(4) {
  [0]=>
  string(4) "this"
  [1]=>
  string(2) "is"
  [2]=>
  string(2) "an"
  [3]=>
  &string(7) "example"
}

Why is this and what functionality / impact does it have?

It is the address pointer. You can `unset($item)` to avoid this — Thamilhan, May 20 '16 at 08:54
@thamilian ah okay, I didn't realize that, could you add that as the answer? — xorinzor, May 20 '16 at 08:56
I must with go @Thamilan, This is a pointer and it points the last element of the array as you use foreach. — Murad Hasan, May 20 '16 at 08:58

Thamilhan · Accepted Answer · 2016-05-20T09:12:45.107

It is the address pointer. You can unset($item) to avoid this.

Answers for your question:

1. Why is this :

You can find the reference in the manual

Warning Reference of a $value and the last array element remain even after the foreach loop. It is recommended to destroy it by unset().

This arises when you use reference in your foreach loop. The reference resides with the last array element.

2. What functionality / impact does it have

Consider this situation:

<?php
$arr = array(1, 2, 3, 4);
foreach ($arr as &$value) {
}

print_r($arr);

foreach ($arr as $value) {
}

print_r($arr);

Your output will be:

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [3] => 4
)
Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [3] => 3  <---
)

If you use unset:

<?php
$arr = array(1, 2, 3, 4);
foreach ($arr as &$value) {
}

print_r($arr);
unset($value);  <---

foreach ($arr as $value) {
}

print_r($arr);

Result will be:

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [3] => 4
)
Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [3] => 4  <---
)

var_dump output using foreach reference loop

1 Answers1