I am new to Scala and I need to have a scala wrapper for my Java API
I have three Java Interfaces
public interface Client<T> {
<T> Future<T> execute(App<T> app);
}
public interface App<T> extends Serializable{
T process(AppContext context) throws Exception;
}
public interface AppContext {
File getDirectory();
void deleteDirectory();
File createDirectory(String path);
}
Following is the Java code to create an App
public class RandomApp extends App<String> {
@Override
public String process(AppContext context) {
// Inorder to access the methods in AppContext I need to access
// it by the following way
appContext.createDirectory("some path");
return "random";
}
}
I want to have a Scala Wrapper for the Client Interface which in turn call the Java API. But I have some modifications for the new Scala API
object ScalaConverter {
implicit class ScalaWrapper(client: Client) {
def scalaClient = new ScalaClient(client)
}
}
class ScalaClient(client: Client) {
def execute[T](appContext: AppContext => T): Future[T] = {
// I am passing appContext as closure instead of passing in
// App because I want to take the advantage of Closures in Scala
// I basically want to create an App with this appContext and
// pass it to the execute method
// For example - but this is not working
var app = // Need to create this app with appContext
Future {
client.execute(app)
}
}
}