64

I have a python dictionary that looks like this:

In[1]: dict_concentration
Out[2] : {0: 0.19849878712984576,
5000: 0.093917341754771386,
10000: 0.075060643507712022,
20000: 0.06673074282575861,
30000: 0.057119318961966224,
50000: 0.046134834546203485,
100000: 0.032495766396631424,
200000: 0.018536317451599615,
500000: 0.0059499290585381479}

They keys are type int, the values are type float64. Unfortunately, when I try to plot this with lines, matplotlib connects the wrong points (plot attached). How can I make it connect lines in order of the key values? enter image description here

DJname
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2 Answers2

125

Python dictionaries are unordered. If you want an ordered dictionary, use collections.OrderedDict

In your case, sort the dict by key before plotting,

import matplotlib.pylab as plt

lists = sorted(d.items()) # sorted by key, return a list of tuples

x, y = zip(*lists) # unpack a list of pairs into two tuples

plt.plot(x, y)
plt.show()

Here is the result. enter image description here

SparkAndShine
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17

Simply pass the sorted items from the dictionary to the plot() function. concentration.items() returns a list of tuples where each tuple contains a key from the dictionary and its corresponding value.

You can take advantage of list unpacking (with *) to pass the sorted data directly to zip, and then again to pass it into plot():

import matplotlib.pyplot as plt

concentration = {
    0: 0.19849878712984576,
    5000: 0.093917341754771386,
    10000: 0.075060643507712022,
    20000: 0.06673074282575861,
    30000: 0.057119318961966224,
    50000: 0.046134834546203485,
    100000: 0.032495766396631424,
    200000: 0.018536317451599615,
    500000: 0.0059499290585381479}

plt.plot(*zip(*sorted(concentration.items())))
plt.show()

sorted() sorts tuples in the order of the tuple's items so you don't need to specify a key function because the tuples returned by dict.item() already begin with the key value.

mhawke
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