C++ in-class initialization

Question

When using in-class initializers, why can I use the copy form of initialization '=' and the braced list form of initialization '{}' but no direct form '()'.

class foo{
    int a = 5;
    int b{5};
    int c(5);
};

Error: expected a type specifier

Error: syntax error: 'constant'

Because that's how the language is specified. – Kerrek SB May 15 '16 at 16:17 — Kerrek SB, May 15 '16 at 16:17
Read about _most vexing parse_ !!! – Destructor May 15 '16 at 16:19 — Destructor, May 15 '16 at 16:19

score 0 · Answer 1 · answered May 15 '16 at 16:24

0

I guess that won't be parsed as variable but it'll be parsed as a declaration of function .That's why it doesn't let u write 5 there .As it is expecting no argument or normal or default type of argument there . And as error also suggests that it is expecting a type specified like int or anything for 5 .And another error suggests that you can not direct pass constant there in the function . It is a syntax error .

answered May 15 '16 at 16:24

Abhishek Panjabi

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It is better not to write answer for duplicate question because it is already answer here on SO !!! – Destructor May 15 '16 at 16:26
I'll keep that in mind from next time . – Abhishek Panjabi May 15 '16 at 16:27

C++ in-class initialization

1 Answers1