Mysterious java.lang.NumberFormatException

Question

I get following exception:

java.lang.NumberFormatException: For input string: "3693019260"

while calling

Integer.parseInt(s);

And I don't know why I get it.

3693019260 is smaller than 2^32
3693019260 is clearly a natural number
the String is cleared from all non-digit elements with s.replaceAll("[^0-9]", "")

So why do I get this exception?

According to the little bit of debugging I did, I saw that the number dips under multmin but I don't know what this variable does and how I should interpret this observation.

You need to describe how you're parsing the string, preferably with your code. — pvg, May 12 '16 at 19:36
Yes, including original code is usually necessary, but I managed to deduce he's using `Integer.parseInt` or one of its friends. — 700 Software, May 12 '16 at 19:38

700 Software · Accepted Answer · 2016-05-12T19:39:54.323

5

While 3693019260 may fit into a 32 bit unsigned integer, it looks like you are trying to parse it into a plain int which is a signed integer. Signed simply means that it supports negative values using -.

With signed numbers, half of the namespace is reserved, so your number must fit into 2^32÷2−1 2147483647 instead of simply 2^32.

The simplest fix is to parse the value as a long instead of an int. Long numbers are 64 bits and support many more digits in the string.

edited May 12 '16 at 19:39

answered May 12 '16 at 19:37

700 Software

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Might want to add that signed int goes up to `2147483647` aka `2^31-1` – Kiskae May 12 '16 at 19:38
ok, that was pretty stupid of me, thanks xD – Armin May 12 '16 at 19:39
@Kiskae He wrote *2^32/2-1* which is the same thing. – RaminS May 12 '16 at 19:39

Mysterious java.lang.NumberFormatException

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