How to convert a clojure keyword into a string?

Question

In my application I need to convert clojure keyword eg. :var_name into a string "var_name". Any ideas how that could be done?

score 184 · Accepted Answer · answered Sep 15 '10 at 15:49

184

user=> (doc name)
-------------------------
clojure.core/name
([x])
  Returns the name String of a string, symbol or keyword.
nil
user=> (name :var_name)
"var_name"

answered Sep 15 '10 at 15:49

kotarak

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3

I cannot imagine a more complete answer, but just for fun I shall dare someone to come up with it. – Hamish Grubijan Sep 15 '10 at 15:55
3

@Hamish Perhaps by adding `(source name)`? – ponzao Sep 15 '10 at 18:05
2

How `name` works should not be of interest. The docstring is the contract. Anything else is an implementation detail, one should not rely upon. – kotarak Sep 15 '10 at 19:32
1

Thanks! My initial reaction was to do this: (.replaceFirst (.toString (keyword "abc")) ":" "") – Susheel Javadi Sep 16 '10 at 06:26
3

Thanks kotarak! I am loving this Clojure more every day! This is my third day. – Santosh Sep 16 '10 at 08:46
@BartJ: `(doc subs)` => `(subs (str (keyword "abc")) 1)` ;) – kotarak Sep 16 '10 at 10:01
5

Maybe this answer should explain why `(name :foo/123/bar)` is "bar". If you want the full path of a keyword you need to use `subs` or something like `(str (namespace k) "/" (name k))` – AnnanFay Apr 06 '12 at 13:48

score 16 · Answer 2 · answered Feb 20 '14 at 19:13

Actually, it's just as easy to get the namespace portion of a keyword:

(name :foo/bar)  => "bar"
(namespace :foo/bar) => "foo"

Note that namespaces with multiple segments are separated with a '.', not a '/'

(namespace :foo/bar/baz) => throws exception: Invalid token: :foo/bar/baz
(namespace :foo.bar/baz) => "foo.bar"

And this also works with namespace qualified keywords:

;; assuming in the namespace foo.bar
(namespace ::baz) => "foo.bar"  
(name ::baz) => "baz"

score 15 · Answer 3 · answered Feb 11 '14 at 01:14

15

Note that kotarak's answer won't return the namespace part of keyword, just the name part - so :

(name :foo/bar)
>"bar"

Using his other comment gives what you asked for :

(subs (str :foo/bar) 1)
>"foo/bar"

answered Feb 11 '14 at 01:14

Rafael Munitić

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Satyam Ramawat · Answer 4 · 2018-10-03T19:49:01.150

It's not a tedious task to convert any data type into a string, Here is an example by using str.

(defn ConvertVectorToString []
 (let [vector [1 2 3 4]]
 (def toString (str vector)))
  (println toString)
  (println (type toString)
(let [KeyWordExample (keyword 10)]
 (def ConvertKeywordToString (str KeyWordExample)))
  (println ConvertKeywordToString)
  (println (type ConvertKeywordToString))

(ConvertVectorToString) ;;Calling ConvertVectorToString Function

Output will be:
1234
java.lang.string
10
java.lang.string

score -2 · Answer 5 · answered Oct 05 '16 at 16:54

-2

This will also give you a string from a keyword:

(str (name :baz)) -> "baz"
(str (name ::baz)) -> "baz"

answered Oct 05 '16 at 16:54

matt whatever

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`str` is not needed in your example. – Vincent Cantin Jan 01 '18 at 12:57

How to convert a clojure keyword into a string?

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