Is it possible to apply destructuring to storing a class method in a variable?

Question

I have the following render method that calls another method in its class:

render() {
   const isValidField = this.isValidField();
}

Is it possible - and if so is it a good idea - to use destructuring in this case to avoid repeating the method name in the variable?

I'm looking for something like this:

render() {
   const { isValidField }() = this;
}

Is `isValidField` the only variable you are getting out of `this` in you `render` method? — nils, May 10 '16 at 14:59
Nope, you can't do this. Your example is a good use-case for getter functions, which can be destructured. — Aaron Beall, May 10 '16 at 16:41

score 0 · Answer 1 · answered May 10 '16 at 15:01

0

You could use a getter function:

get isValidField() {
    return true;
}

render() {
    const {isValidField} = this;
}

answered May 10 '16 at 15:01

Aaron Beall

1 Answers1