How to simplify the IF statement in Python 3

Question

I have the IF statement as follows:

...
if word.endswith('a') or word.endswith('e') or word.endswith('i') or word.endswith('o') or word.endswith('u'):
...

Here I had to use 4 ORs to cover all the circumstances. Is there anyway I can simplify this? I'm using Python 3.4.

Check this: http://stackoverflow.com/questions/22812785/use-endswith-with-multiple-extensions — galah92, May 09 '16 at 06:03
Also here which sort of explains it: http://stackoverflow.com/a/18351977/390450 — Te-jé Rodgers, May 09 '16 at 06:07

score 3 · Answer 1 · answered May 09 '16 at 06:01

3

Use any

>>> word = 'fa'
>>> any(word.endswith(i) for i in ['a', 'e', 'i', 'o', 'u'])
True
>>> word = 'fe'
>>> any(word.endswith(i) for i in ['a', 'e', 'i', 'o', 'u'])
True
>>>

answered May 09 '16 at 06:01

Avinash Raj

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like in someone answer's you may also use `"aeiou"` instead of a list `['a', 'e']` since both list and string are iterables in python – Avinash Raj May 09 '16 at 06:05

score 2 · Accepted Answer · answered May 09 '16 at 06:03

2

Try

if word[-1] in ['a','e','i','o','u']:

where word[-1] is the last letter

answered May 09 '16 at 06:03

Hafees Kazhunkil

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AKS · Answer 3 · 2016-05-09T06:23:09.187

1

Simply:

>>> "apple"[-1] in 'aeiou'
True
>>> "boy"[-1] in 'aeiou'
False

edited May 09 '16 at 06:23

answered May 09 '16 at 06:01

AKS

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score 0 · Answer 4 · answered May 09 '16 at 06:07

word.endswith(c) is just the same as word[-1] == c so:

VOWELS = 'aeiou'

if word[-1] in VOWELS:
    print('{} ends with a vowel'.format(word)

will do. There is no need to construct a list, tuple, set, or other data structure: just test membership in a string, in this case VOWELS.

How to simplify the IF statement in Python 3

4 Answers4