In python: unable to convert variable with uint32_t, uint8_t, int16_t value to hexadecimal

Question

I have a .ini file with values as below

[Value1]
data_type = uint16_t
value = 0x0001U


[Value2]
data_type = uint32_t
value = 0x00000002UL

[Value4]
data_type = uint8_t
value = 5U

I am unable to convert these values to hexadecimal as below Comment: I am easily able to read .ini file using configparser. Let assume i have value as string in variable var and I want to convert that string variable to hex form

print (hex(var)) #this should print the  hexadecimal value

using config parser ...that is not a issue ...lets assume i have value in variable in string form ....how should i proceed after that ? — Ravi Yadav, May 04 '16 at 08:43
This is an important precision, I couldn't guess what your variable `value` contained. Also, what error does your command raises? — Arcturus B, May 04 '16 at 08:46

score 3 · Accepted Answer · answered May 04 '16 at 08:47

3

This doesn't work:

var = '0x00000002UL'
hex(var)

Because hex() is meant to convert in the opposite direction. Instead, try this:

var = '0x00000002UL'
int(var[:-2], 16)

Note you need to skip the UL on the end because that's not Python syntax.

answered May 04 '16 at 08:47

John Zwinck

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In python: unable to convert variable with uint32_t, uint8_t, int16_t value to hexadecimal

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