How can I accomplish this with unpivot and pivot.
I've seen this question asked before and has a solution with case statement and union all
In SQL, how can I count the number of values in a column and then pivot it so the column becomes the row?
and here PIVOT/UNPIVOT multiple rows and columns but I have 20 rows and 24 columns and the query would become very long and I suspect inefficient. Does anyone know how I can do this with unpivot and pivot or is case and union all the only viable option?
Hour A B C D E ... Z
-----------------------------------------
0 4 2 3 0 6 2
1 3 5 7 1 8 7
2 2 6 1 1 4 3
3 2 2 0 3 0 2
4 3 9 6 2 2 8
...
23 6 5 2 3 8 6
Field 0 1 2 3 ...23
-------- -- -- -
A 2 0 2 2 4
B 7 2 8 1 6
....
Z 6 7 7 3 8
This is what I've tried in terms of pivot but I didn't get far:
select B,[0],[1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12],[13],[14],[15],[16],[17],[18],[19],[20],[21],[22],[23] from CTE2
pivot(
sum(A)
for hour in ([0],[1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12],[13],[14],[15],[16],[17],[18],[19],[20],[21],[22],[23])) as pvt;
Just to clarify, the numbers in the table are just random numbers I've put to simulate data, they aren't transposed as they should be.