how to emulate linux command - "source filename -arg value" in python

Asked Apr 30 '16 at 03:16

Active May 02 '16 at 16:23

Viewed 165 times

I am trying to script the Linux instructions in python. I am not able to script the following in python.

source /usr/home/modelling.rc -m model

I tried subprocess.call(['/usr/home/modelling.rc', "-m", "model"]) ***E: You can't execute me directly, you must source me! source /usr/home/modelling.rc -m model

I also found that execfile() does the same job as source. But without giving the arguments, I am not able to run the file. Is there a way to source the file with arguments in python. Please help!

Thanks

edited May 02 '16 at 16:23

asked Apr 30 '16 at 03:16

user3798648

Like [`subprocess`](https://docs.python.org/2/library/subprocess.html#module-subprocess) or what? – stackoverfloweth Apr 30 '16 at 03:20
I think you can't have it both ways (execute bash commands on a child, and modify a parent environment). – xvan Apr 30 '16 at 03:20
I am not sure if subprocess can do this.if you think it will, please help me.. – user3798648 Apr 30 '16 at 06:08
1

@user3798648, what did you try? Post in your question. – stackoverfloweth Apr 30 '16 at 14:31

how to emulate linux command - "source filename -arg value" in python

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