Append to a tuple of a array

Question

I would like to add a backslash all doublepoints in a tuble that is in a array...

The code I have:

def removeDots (input):
    for i in input:
        p = i[2]
        p.replace(":","\:")
        liste = list(i)
        liste.append(p)
        liste = tuple(i)
    return input

Example:

Before: [('Hello:bye','Hello:bye'),('Bye:Hello','Bye:Hello')]
After: [('Hello:bye','Hello\:bye'),('Bye:Hello','Bye\:Hello')]

please give us a minimal reproducible example: http://stackoverflow.com/help/mcve — Stefano, Apr 28 '16 at 14:12
Fixed it... Didn't showed the backslash after i posted it... — itspat, Apr 28 '16 at 14:15
I am not sure I fully understand what this piece of code should do. you return the input... of course it does nothing! — Stefano, Apr 28 '16 at 14:15
@Stefano It should just do it for cell 9 and not for every cell... Will fix it... — itspat, Apr 28 '16 at 14:16
so why do you use a loop? and in your after you modified element 1 & 2... not the 9th... sorry but I am still a bit confused — Stefano, Apr 28 '16 at 14:17
@Stefano Because it should do it for every tuble but just for cell 2 — itspat, Apr 28 '16 at 14:19

score 1 · Answer 1 · answered Apr 28 '16 at 14:20

1

This should work:

def remove_dots(data):
    return [tuple(s.replace(":", "\:") for s in row) for row in data]

answered Apr 28 '16 at 14:20

Alex Hall

34,833
5
57
89

This outputs: `[('H', 'e', 'l', 'l', 'o', '\\:', 'b', 'y', 'e'), ('B', 'y', 'e', '\\:', 'H', 'e', 'l', 'l', 'o')]` for `remove_dots([('Hello:bye'),('Bye:Hello')])` – Lafexlos Apr 28 '16 at 14:22
@Lafexlos but that input is incorrect and has been changed in the question. Each element of the input should be a tuple, not just a string. – Alex Hall Apr 28 '16 at 14:24
Sorry, then. My bad. Didn't notice that. – Lafexlos Apr 28 '16 at 14:25
Returned erroe `TypeError: an integer is required` – itspat Apr 28 '16 at 14:32
@AlexHall `def remove_dots(x): return [tuple(s.replace(":", "\:") for s in row) for row in x] resultSiDynamicData = cur.fetchall() resultSiDynamicDataReturn = remove_dots(resultSiDynamicData)` – itspat Apr 28 '16 at 14:38

score 1 · Accepted Answer · answered Apr 28 '16 at 14:29

1

def removeDots (x):
    p = []
    for i in x:
        p.append((i[0],i[1].replace(":","\\:")))
    return p

x = [('Hello:bye','Hello:bye'),
    ('Bye:Hello','Bye:Hello')]

print x
print removeDots(x)

answered Apr 28 '16 at 14:29

Stefano

3,981
8
36
66

you will see \ printed twice... this is normal: http://stackoverflow.com/questions/24085680/why-do-backslashes-appear-twice – Stefano Apr 28 '16 at 14:34
seems to work! will shortly try it in the productive environment... Thank you verry much! – itspat Apr 28 '16 at 14:40
Worked perfectly, thank you!!! Sorry for my errors with the example and everything... – itspat Apr 28 '16 at 14:45
I can't, my score is to low :/ @Stefano – itspat Apr 29 '16 at 09:18

DCA- · Answer 3 · 2016-04-28T14:30:27.960

0

Here's a basic example of what i think you're looking for. You will need to adjust it to suit your case specifically.

def removeDots(x):
    p = []
    for i in x:
        p.append((i[0],i[1].replace(":","\\:")))
    return p

x = [('Hello:bye','Hello:bye'),('Bye:Hello','Bye:Hello')]
print removeDots(x)

Remember to escape the backslash!

edited Apr 28 '16 at 14:30

answered Apr 28 '16 at 14:21

DCA-

1,262
2
18
33

score 0 · Answer 4 · answered Apr 28 '16 at 14:37

0

def removeDots(input):
    res = list()
    for x, y in input:
        res.append((x,y.replace(":","\\:")))
    return res

answered Apr 28 '16 at 14:37

Daniel

573
6
14

Append to a tuple of a array

4 Answers4