Regular expression in python with urlParse

Question

I have this URL:

https://www.yoursite.com/drive/team-real-431/pepe-ozil-R323/anyway-jim-james-hi-bye-hi-321312/;jsessionid=DBDE454034B0EE325FC100112EF2E123.56AC29295781342F53AB242D03EE33

i want to have

DBDE454034B0EE325FC100112EF2E123.56AC29295781342F53AB242D03EE33

i tried

ulrJS = "https://www.yoursite.com/drive/team-real-431/pepe-ozil-R323/anyway-jim-james-hi-bye-hi-321312/;jsessionid=DBDE454034B0EE325FC100112EF2E123.56AC29295781342F53AB242D03EE33"
ulrJS = ulrJS.split('/')[-1]

@Francesco thanks, i edited my question – parik Apr 27 '16 at 08:56 — parik, Apr 27 '16 at 08:56

AKS · Accepted Answer · 2016-04-27T08:55:56.733

1

You can use urlparse:

>>> import urlparse
>>> url = 'https://www.yoursite.com/drive/team-real-431/pepe-ozil-R323/anyway-jim-james-hi-bye-hi-321312/;jsessionid=DBDE454034B0EE325FC100112EF2E123.56AC29295781342F53AB242D03EE33'
>>> url_parts = urlparse.urlparse(url)
>>> jsessionid = dict(urlparse.parse_qsl(url_parts.params)).get('jsessionid')
>>> print(jsessionid)
DBDE454034B0EE325FC100112EF2E123.56AC29295781342F53AB242D03EE33

edited Apr 27 '16 at 08:55

answered Apr 27 '16 at 08:52

AKS

18,983
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i use python 2.7, i got this error: jsessionid = dict(urlparse.parse_qsl(url_parts.params)).get('jsessionid') NameError: name 'url_parts' is not defined – parik Apr 27 '16 at 08:54

score 0 · Answer 2 · answered Apr 27 '16 at 08:57

0

from urlparse import urlparse
url ="https://www.yoursite.com/drive/team-real-431/pepe-ozil-R323/anyway-jim-james-hi-bye-hi-321312/;jsessionid=DBDE454034B0EE325FC100112EF2E123.56AC29295781342F53AB242D03EE33"
u = urlparse(url)
print u.params.split("=")[1]
'DBDE454034B0EE325FC100112EF2E123.56AC29295781342F53AB242D03EE33'

answered Apr 27 '16 at 08:57

Mani

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Better to use `urlparse.parse_qsl` just in case you have other params other than `jsessionid`. – AKS Apr 27 '16 at 09:02

Regular expression in python with urlParse

2 Answers2