Converting an int to an unsigned char in C

Question

I've never needed to use unsigned char before, but I've recently became curious about their ability to store integers. Through a little bit of reading I have done I've found that the cast from int to unsigned char is done implicitly, but I have also explicitly added the cast. Either way, the code below does not work and either prints out the alphabet letter equivalent or a small empty box.

printf("%s", "Number: ");
int input;
scanf("%d", &input);  
unsigned char num = input;
printf("%c%s%d", num, " = ", input);
return (EXIT_SUCCESS);

It will print the equivalent alphabet until you overflow it, in this case in prints nothing just like 0. — Ouss4, Apr 27 '16 at 00:19

score 1 · Answer 1 · answered Apr 27 '16 at 00:22

1

You are printing out the number as a character (%c) instead of an integer (%hhu).

answered Apr 27 '16 at 00:22

Remy Lebeau

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score 1 · Answer 2 · answered Apr 27 '16 at 00:22

1

In printf, the %c means to print the character symbol whose code is the corresponding argument.

To print the numeric value use %d instead.

answered Apr 27 '16 at 00:22

M.M

138,810
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score 0 · Answer 3 · answered Apr 27 '16 at 00:27

0

It prints a letter because you set printf() to print num's value as a character with "%c". If you use "%d" for example you can print its numeric value.

answered Apr 27 '16 at 00:27

LeonMarchetti

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Converting an int to an unsigned char in C

3 Answers3