How to filter out files with multiple criteria in a Makefile?

Question

Lets say you filter for cpp files like so

$(wildcard **/*.cpp)

But you don't want files that contain the word foo and you don't want the file with the exact name bar.cpp

How does one use filter-out with multiple criteria?

Wanted to point out that if you think using the `**` construct will cause make's `wildcard` function to search directories recursively like zsh does... it won't. — MadScientist, Apr 21 '16 at 12:41

Johnny Haddock · Accepted Answer · 2016-05-05T12:41:32.713

8

This seems to work. Also recursively.

$(filter-out $(wildcard **/bar.cpp) $(wildcard **/*foo*), $(wildcard **/*.cpp))

Please also note Etan's simpler suggestion below. Leaving mine only for completeness.

edited May 05 '16 at 12:41

answered Apr 19 '16 at 13:48

Johnny Haddock

3

You don't need to `$(wildcard)` for `bar.cpp` just `%/bar.cpp` will work. – Etan Reisner Apr 19 '16 at 13:50
Even if it's in a subdirectory? – Johnny Haddock Apr 19 '16 at 16:02
2

Yup, even with subdirectories. The `%` matches anything. Try it and see. – Etan Reisner Apr 19 '16 at 16:12

1 Answers1