How to use re.findall to get the url string?

Question

"foldGroup.registerImage({ domId: 'listimg7', srcUrl: 'https://ec.yimg.com/ec/?url=https%3A%2F%2Fd3vv6xw699rjh3.cloudfront.net%2F9f689b-1904037587_1_160.jpg&t=1460964135&ttl=43200&maxWidth=160&maxHeight=160&sig=QSY1BP0sCebMxqEN6irjXQ--~C' });"

This is a part of the html from a yahoo shopping page, like:
https://shopping.yahoo.com/womens-intimate-apparel/?b=3937

My question is how to find all the img urls using the Python's re.findall()?

because there javascrip code in html,the page crawled can be parsed fully — mingxin zhao, Apr 18 '16 at 07:57

score 2 · Accepted Answer · answered Apr 18 '16 at 07:53

re.findall(r"'https://.*?'", part_of_html)

re.findall(pattern, string, flags=0) Return all non-overlapping matches of pattern in string, as a list of strings. The string is scanned left-to-right, and matches are returned in the order found. If one or more groups are present in the pattern, return a list of groups; this will be a list of tuples if the pattern has more than one group. Empty matches are included in the result unless they touch the beginning of another match.

thank you, that is really helpful – mingxin zhao Apr 18 '16 at 08:03 — mingxin zhao, Apr 18 '16 at 08:03

How to use re.findall to get the url string?

1 Answers1