Finding Min/Max numbers in a java array

Question

I am making a program that finds the min/max numbers in a java array. I am currently stuck at the last part which is finding the min/max. I have currently setup all other parts of the program. This is my code.

import java.util.Scanner;
public class X {
public static void main (String[] args) {
    Scanner input= new Scanner(System.in);
    System.out.println("Enter size of array");
    int n= input.nextInt();
    int[] x= new int[n];
    System.out.println("Enter Array nums");
    for(int i=0;i<n;i++){
        x[i]= input.nextInt();
    }}}

loop through the array and compare the values, which you haven´t done yet — SomeJavaGuy, Apr 15 '16 at 06:25
You haven't tried anything. So first try to find the solution yourself and show us where you're hanging. — Roemer, Apr 15 '16 at 06:26
Sorry, this is not a "please, do my homwork for free" website. If you have questions, you are welcome to ask them, but you can't ask people to do something for you without trying first. — Matthieu Moy, Apr 15 '16 at 06:36

score 1 · Answer 1 · answered Apr 15 '16 at 06:26

1

Arrays.sort(x);

sorts the array, so after doing that all you need to do is look in the first and last element to find the min and max.

answered Apr 15 '16 at 06:26

nhouser9

6,730
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score 0 · Answer 2 · answered Apr 15 '16 at 06:28

0

You can use the following methods to directly find the max and min.

List list = Arrays.asList(x);
System.out.println(Collections.min(list));
System.out.println(Collections.max(list));

answered Apr 15 '16 at 06:28

Imesha Sudasingha

3,462
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score 0 · Answer 3 · answered Apr 15 '16 at 06:29

simple.

So Simple actually

public static void main(String[] args)
{
    Scanner input= new Scanner(System.in);
System.out.println("Enter size of array");
    int n= input.nextInt();
    int[] x= new int[n];
    System.out.println("Enter Array nums");
    for(int i=0;i<n;i++){
        x[i]= input.nextInt();
    }}}
    Arrays.sort(x);
    System.out.println(String.format("Min= %d Max= %d",x[0],x[x.length -1]));
}

score 0 · Answer 4 · answered Apr 15 '16 at 06:39

import java.util.Scanner;
public class X {
public static void main (String[] args) {
Scanner input= new Scanner(System.in);
System.out.println("Enter size of array");
int n= input.nextInt();
int[] x= new int[n];
int min_num,max_num;
System.out.println("Enter Array nums");
for(int i=0;i<n;i++){
    x[i]= input.nextInt();
    if(i==0){
        min_num=max_num=x[i];
    }else{
        if(x[i]>max_num)
        max_num=x[i]; 
        if(x[i]<min_num)
        min_num=x[i];
    }}}

Finding Min/Max numbers in a java array

4 Answers4