What does the following mean when written in a subclass:
public override bool IsReadOnly
=> false;
Does this differ from:
public override bool IsReadonly
{
get
{
return false;
}
}
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steve_cdi
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1No; this is a new syntatic sugar in C# 6. – SLaks Apr 14 '16 at 17:36
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Sorry I misunderstood what you mean when you say No; Are the two statements equivalent or is there a subtle difference? – steve_cdi Apr 14 '16 at 17:39
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@SLaks what is the name of this sugar? – KDecker Apr 14 '16 at 17:45
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@steve_cdi No, there is no difference between the two. – itsme86 Apr 14 '16 at 17:51
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This is an _expression-bodied member_. – BJ Myers Apr 14 '16 at 17:52
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https://msdn.microsoft.com/en-us/magazine/dn802602.aspx – SLaks Apr 14 '16 at 17:52
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"syntactic sugar" means better (more "sugary" syntax) that does the same thing. – Lasse V. Karlsen Apr 14 '16 at 17:56
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Thank you SLaks, very quick response and much appreciated. My first question so I'm unfamiliar with the rewards system, but I understand that I can't mark a comment as an answer. I will mark Arturo's answer below if that's OK. – steve_cdi Apr 14 '16 at 18:07
2 Answers
2
What does the following mean when written in a subclass
This is a new feature in C# 6.0 called Expression Body, this is a syntactic sugar that allows define getter-only properties and indexers where the body of the getter is given by the expression body.
Does this differ from
No, there is no difference between this and the classic form, is just an syntactic sugar.
Methods as well can be defined as an expression-bodied:
public void PrintLine(string line) => Console.WriteLine(line);
Arturo Menchaca
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Its the same thing, there is no difference, like our friend Slaks said, its just syntactic sugar. "=>" is the lambda expression of assignment.
Ricardo Olivo Poletti
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