Deserialize Json with minus in property name

Question

I have a JSON return as below.

   {
    "id": 100,
    "name": "employer 100",
    "externalId": "100-100",
    "networkId": 1000,
    "address": {
        "street-address": "1230 Main Street",
        "locality": "Vancouver",
        "postal-code": "V6B 5N2",
        "region": "BC",
        "country-name": "CA"
    }
   }

So I created class to deserialize the above json.

    public class Employer
        {
            public int id { get; set; }
            public string name { get; set; }
            public string externalId { get; set; }
            public int networkId { get; set; }
            public Address address { get; set; }
        }
    public class Address
        {
            public string street_address { get; set; }
            public string locality { get; set; }
            public string postal_code { get; set; }
            public string region { get; set; }
            public string country_name { get; set; }
        }

var response = _client.Execute(req); 
return _jsonDeserializer.Deserialize <Employer> (response);

But I could not get street-address, postal-code and country-name from Json string. I think because of Json output keys contain ""-"" (As result of that I'm getting null).

So how could I resolve my issue ?

Which library do you use for deserialization? – Eser Apr 13 '16 at 20:26 — Eser, Apr 13 '16 at 20:26
Updated my answer for RestSharp – JimBobBennett Apr 13 '16 at 21:20 — JimBobBennett, Apr 13 '16 at 21:20

JimBobBennett · Accepted Answer · 2016-04-13T21:20:20.177

5

Use the DeserializeAs attribute on your properties:

[DeserializeAs(Name = "postal-code")]
public string postal_code { get; set; }

This allows you to set the same of the property in the json that maps to the property in your class, allowing the property to have a different name to the son.

https://github.com/restsharp/RestSharp/wiki/Deserialization

edited Apr 13 '16 at 21:20

answered Apr 13 '16 at 20:25

JimBobBennett

2,149
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if OP uses JsonNet – Eser Apr 13 '16 at 20:25
I'm assuming based on the JsonDeserializer.Deserialize that they are, but I should clarify. Will edit. – JimBobBennett Apr 13 '16 at 20:26
And exactly this code make me think it may be another library like RestSharp. – Eser Apr 13 '16 at 20:31
I guess the comment 'Im using RestSharpe' probably adds weight to your thoughts @Eser ;) – JimBobBennett Apr 13 '16 at 20:51
I din't see it. If I had, I would have downvoted this ;) – Eser Apr 13 '16 at 20:58
It was added later as an edit – JimBobBennett Apr 13 '16 at 21:17
@JimBobBennett Awesome dude. all good. much appreciate it. :) Thank you – Gayan Apr 13 '16 at 21:29

Whit Waldo · Answer 2 · 2016-04-14T01:27:20.267

1

If you're using JSON.net, use attributes on your properties to specify the names that they should match up to:

public class Employer
{
    public int id { get; set; }
    public string name { get; set; }
    public string externalId { get; set; }
    public int networkId { get; set; }
    public Address address { get; set; }
}
public class Address
{

    [JsonProperty("street-address")]
    public string street_address { get; set; }
    public string locality { get; set; }
    [JsonProperty("postal-code")]
    public string postal_code { get; set; }
    public string region { get; set; }
    [JsonProperty("country-name")]
    public string country_name { get; set; }
}

edited Apr 14 '16 at 01:27

answered Apr 13 '16 at 20:26

Whit Waldo

4,806
4
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I dont think this gonna be work hence street-address as street_address – Gayan Apr 13 '16 at 21:05
@GayanJ Easily solved, just change the string within the quotes. I've updated my answer to reflect the change to use a dash instead of an underline. – Whit Waldo Apr 14 '16 at 01:27

Deserialize Json with minus in property name

2 Answers2