How to create function variables with parameter in extensions?

Question

When working with Swift - Extensions

As you know, we can create variables for function. i want to create a variable which can hold reference to a function which has parameters.

i have managed to create variable for a function which didn't have any parameters defined for

My code is as follows :-

extension UIAlertController {


    var cancelBlock : ()->Void  { return {} }

    var nameBlock : (nameArg:String?)->Void  { }

}

I am getting the following error with "nameBlock"

Computed property must have accessors specified

How should i specify return value ?

You need to create a method `func nameBlock(parameter: Type) -> TypeToReturn { ... }` — Leo Dabus, Apr 11 '16 at 06:21
@LeoDabus I want to use this function variable as block / closure . (i.e replace this with another block of code in a function defined in the extension ). how will i be able to do that — Pawan Joshi, Apr 11 '16 at 06:30
What exactly do you mean by "replace this with another block"? Extensions don't allow stored properties, anyway, so you'll have to store it somewhere yourself. — jtbandes, Apr 11 '16 at 06:36

score 0 · Accepted Answer · answered Apr 11 '16 at 06:43

0

use
var nameBlock : (nameArg:String?)->Void? { return nil }

answered Apr 11 '16 at 06:43

rahulchona

this is a computed property that should return an optional method but instead of it it always returns nil. I am still trying to understand what would be the use of it – Leo Dabus Apr 11 '16 at 06:55

1 Answers1