-6

I have a word (can't provide it here) and its encrypted code: 

1C6FC813B5D83F96BB5A4B62F421225E060AC2FCD3A2C4C31B029D92C96444AB6F943DE9B6D83764C8AC5DF743DF9A1FFAC14686B531BF2CDA551F561

I should find the encryption algorithm used for it. I tried SHA-512 and generated me the same code as below but by including some zeroes. I tried many online SHA generators and they all provided the same below encrypted code.

1c6fc813b5d83f960bb5a4b62f421225e060ac2fcd3a2c4c31b029d92c96444ab6f943de09b6d83764c8ac5df743df9a1ffac146860b05031bf2cd0a551f5601

Any idea about how some zeros are excluded?

Robin V.
  • 1,484
  • 18
  • 30
user2885307
  • 11
  • 2

1 Answers1

1

That are the same SHA-512 hashes displayed in hexadecimal with the following exception: In the top hash all bytes that in hex would have a leading 0 it was dropped, probably the binary to hexadecimal conversion was incorrect. Perhaps the format was %x instead of %02x.

Example:

printf("%x%x%x%x\n",         0x55, 0x02, 0x40, 0x66);
printf("%02x%02x%02x%02x\n", 0x55, 0x02, 0x40, 0x66);

Output:

5524066 <-- Notice the missing 0
55024066

zaph
  • 111,848
  • 21
  • 189
  • 228