Cannot locate link css or xpath

Question

I started to learn ruby (rspec , rubymine). I want to do simple click action but I have a problem. Id and name does not exist so, I should use xpath or css.

I tried #click on contact link:

driver.find_element(:css, 'html>body>footer>div>div>section:nth-child(3)>a:nth-child(1)').click + ' :: absolute path'

xpath showed me:

 /x:html/x:body/x:footer/x:div/x:div/x:section[3]/x:a[1]

link is:

<a href="/k/k.aspx?action=custserv&amp;topic=contact" title="Contakt ">Contact</a>

and this is FIRST link in:

section class="link-block link-collection col-xs-12 col-sm-4 col-md-2"

and section class is placed in div: class="row"

and this is here: <footer class="footer" role="info">

and this is inside: <body data-touch="false" class="abc">

enter image description here

Can anybody help me?

You could go by the link text content here, that's more save for future changes. — Thomas R. Koll, Apr 03 '16 at 15:53
link text content here, so where and how?:) something was not copied i think: Contact — gadzet, Apr 03 '16 at 15:58
works with:driver.find_element(:xpath, '//*[@title="Contact"]').click but when title will change it will not work.. — gadzet, Apr 03 '16 at 18:26
Is this is a spec? Then yes - when the text changes... the spec should fail and then you change the spec to the new text. For a capybara spec you are expected to test what the user actually sees - ie click on the content that is actually displayed to the user... not the CSS classes. — Taryn East, Apr 04 '16 at 00:27

Justyna J · Answer 1 · 2016-04-04T20:42:14.607

0

I used now Css but...it clicks on another links and css is the same! strange..hm css: .footer .container .row .link-block h4 + a

so, how can I do this with xpath?;/ I used @driver.find_element(:xpath, '//html/body/footer/div/div/section[3]/a[1]').click and it works:) but..what if sth will be changed on page?

edited Apr 04 '16 at 20:42

answered Apr 04 '16 at 20:10

Justyna J

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Cannot locate link css or xpath

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