kue - Processing jobs in different file

Question

I want my queue.process function to be in a separate file, but module.exports doesn't work.

kue.js:

var kue = require('kue');
module.exports = function() {
  var queue = kue.createQueue();
  queue.process('test', function(job, done) {
    console.log('job processed.');
    done();
  }
}

server.js:

require('./kue');
//server stuff

There are no errors. I also have a separate function queuing jobs and its working. The problem seems to be in importing kue.js file.

score 3 · Accepted Answer · answered Apr 02 '16 at 12:26

3

You are exporting a function in kue.js, but you aren't calling that function when you require it. Try

 require('./kue')();

answered Apr 02 '16 at 12:26

Robert Moskal

21,737
8
62
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That's silly of me, thanks, I totally forgot that I need to invoke a function. – Chris Kraszewski Apr 02 '16 at 12:28

score 1 · Answer 2 · answered Apr 02 '16 at 12:24

1

You should require name the function you are exporting for example

module.exports.proccess = function()...

answered Apr 02 '16 at 12:24

Marko vlaić

316
5
15

That works, but Robert's answer is exactly what I was looking for. – Chris Kraszewski Apr 02 '16 at 12:29
1

Glad that you found a solution :) – Marko vlaić Apr 02 '16 at 13:14

kue - Processing jobs in different file

2 Answers2