Financial calculation with JavaScript (What´s wrong?)

Question

I'm trying to make a financial calculation, but there's something wrong.

JS Code:

function count (){

var coda = 1.500;
var codb = 15;
var codc = 0.06;
var codx = 1;

var result = (codc/codx(codx-((codx+codc)*-codb)))*coda;

alert(result);


}

Message: undefined

`codx(...)` is parsed as invocation of `codx` function, but it is not a function. — pawel, Mar 29 '16 at 11:58

score 1 · Answer 1 · answered Mar 29 '16 at 11:59

1

In this line var result = (codc/codx(codx-((codx+codc)*-codb)))*coda;

You try to execute the 2nd codx as a function (codx()). I guess you miss an operand there.

Try for example: var result = (codc/codx / (codx-((codx+codc)*-codb)))*coda;

answered Mar 29 '16 at 11:59

Pimmol

1,871
1
8
14

score 0 · Accepted Answer · answered Mar 29 '16 at 11:56

You are missing a * operator, so the compiler tries to call codx as a function.

To fix your computation, add the * operator as follow:

function count (){

    var coda = 1.500;
    var codb = 15;
    var codc = 0.06;
    var codx = 1;

    var result = (codc/codx * (codx - ((codx+codc)*-codb)))*coda;
    //                      ^

    alert(result);
}

score 0 · Answer 3 · answered Mar 29 '16 at 11:59

0

Missing * symbol? codx is being used as a fuction as a result.

var coda = 1.500;
var codb = 15;
var codc = 0.06;
var codx = 1;

var result = (codc/codx*(codx-((codx+codc)*-codb)))*coda;

alert(result);

answered Mar 29 '16 at 11:59

Paul Humphreys

338
2
9

score 0 · Answer 4 · answered Mar 29 '16 at 12:00

0

Slightly off-topic but you should never use floating point arithmetic in financial calculations. Instead calculate by integer cents and then format for viewing as you like.

answered Mar 29 '16 at 12:00

teroi

1,087
10
19

score 0 · Answer 5 · answered Mar 29 '16 at 12:00

In this case,

It is better to split the mathematical calculation.

Example:

function count (){

var coda = 1.500;
var codb = 15;
var codc = 0.06;
var codx = 1;

var res1 = ((codx+codc)*-codb);
var res2 = codx-res1;
var result = (codc/codx*res2)*coda;

alert(result);

}

score 0 · Answer 6 · answered Mar 29 '16 at 12:02

var count = function () {
 var coda = 1.5; var codb = 15; var codc = 0.06; var codx = 1;
 var result = (codc/codx ** here ** (codx-((codx+codc)* - codb))) *  coda;    
 console.log(result);
}

P.S you have to put something after codx it's seen by javascript as an undefined function.

score 0 · Answer 7 · answered Mar 29 '16 at 15:18

If this relates to paying down a loan at interest i per payment period, then you get that after n payments at a rate of r the reduced principal is

p*(1+i)^n-r*(1+i)^n-r*(1+i)^(n-1)-...-r*(1+i) 
=
p*(1+i)^n - (1+i)*((1+i)^n-1)/i*r

If that is to be zero, loan repaid, then the necessary rate computes as

r = i/((1+i)*(1-(1+i)^(-n))) * p

which is in some aspects similar, in other fundamental aspects different from your formula.

var p = 1.500;
var n = 15;
var i = 0.06;
var x = 1+i;

var result = i/( x*( 1-Math.pow(x,-n) ) )*p;

alert(result);

Financial calculation with JavaScript (What´s wrong?)

7 Answers7