how can i use biginteger to operate with binaries values

Question

I'm working with java, and I'm trying to play with numbers in different bases (2,8 and 10).

So, I'm asking this question to change a binary number in string format into number in base 10

such as 11000000101010000000000000111111/base 2

I tried Integer.parseInt(str,radix) however I got errors. exepetion ""Exception in thread "main" java.lang.NumberFormatException: For input string: "11000000101010000000000000111111" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source)

Maybe this helps http://stackoverflow.com/questions/8548586/adding-binary-numbers — RubioRic, Mar 29 '16 at 11:33
i've used `Integer.parseInt()` it does not work any other ideas — azdoud, Mar 29 '16 at 11:34
The answer that I pointed you not only just parses Integer, it parses specifying a radix. — RubioRic, Mar 29 '16 at 11:48
thank you too @RubioRic, yes it uses radix but when i used Integer.parseInt(str,radix) the SE throws me this exepetion ""Exception in thread "main" java.lang.NumberFormatException: For input string: "11000000101010000000000000111111" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) "" so i asked this question — azdoud, Mar 29 '16 at 11:54
FWIW, I don't think this is off-topic. It may be a duplicate, though, of the question linked to by RubioRic. — Rudy Velthuis, Mar 29 '16 at 16:18

score 5 · Answer 1 · answered Mar 29 '16 at 11:34

BigInteger provides a BigInteger(String,int) constructor, where you can define the radix. You could simply create two instances, one for the initial value, and one for the 1. Further on you´d just need to use BigInteger#add.

After this is done, there´s also a toString(radix) function for BigInteger, where you can display the result for a different radix.

public static void main(String[] args) {
    BigInteger base = new BigInteger("11000000101010000000000111111111", 2);
    BigInteger one = new BigInteger("1", 2);
    BigInteger result = base.add(one);
    System.out.println(result.toString(2));
}

output

11000000101010000000001000000000

thank you @Kevin that's exactly what I'm looking for – azdoud Mar 29 '16 at 11:41 — azdoud, Mar 29 '16 at 11:41

how can i use biginteger to operate with binaries values

1 Answers1