It feels like a pretty common problem and there is no easy annotations way to solve it (Or maybe i just cant find one):
Jackson Polymorphic Deserialization - Can you require the existence of a field instead of a specific value?
Deserializing polymorphic types with Jackson
One thing you can do is to add custom deserializer to your object mapper. Here is nice demo of this approach: https://stackoverflow.com/a/19464580/1032167
Here is demo related to your example:
import com.fasterxml.jackson.annotation.*;
import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.core.ObjectCodec;
import com.fasterxml.jackson.databind.*;
import com.fasterxml.jackson.databind.module.SimpleModule;
import java.io.IOException;
public class Main4 {
private static final String jsonA = "{ \"keys\" : { \"primary_key\" : \"abc\" } }";
private static final String jsonB =
"{ \"keys\" : { \"primary_key\" : \"abc\", \"secondary_key\" : \"xyz\" } }";
public static void main(String[] args) throws IOException {
ObjectMapper mapper = new ObjectMapper();
SimpleModule idAsRefModule = new SimpleModule("ID-to-ref");
idAsRefModule.addDeserializer(A.class, new AJsonDeserializer());
mapper.registerModule(idAsRefModule);
X tl = mapper.readValue(jsonA, X.class);
System.out.println(tl);
X t2 = mapper.readValue(jsonB, X.class);
System.out.println(t2);
}
public static class AJsonDeserializer extends JsonDeserializer<A>{
@Override
public A deserialize(JsonParser jp, DeserializationContext dc)
throws IOException {
ObjectCodec codec = jp.getCodec();
JsonNode node = codec.readTree(jp);
if (node.has("secondary_key")) {
return codec.treeToValue(node, B.class);
}
return new A(node.findValue("primary_key").asText());
}
}
public static class A
{
@JsonProperty("primary_key")
public final String primaryKey;
@JsonCreator
A(@JsonProperty("primary_key") String primaryKey)
{
this.primaryKey = primaryKey;
}
@Override
public String toString() {
return "A{" +
"primaryKey='" + primaryKey + '\'' +
'}';
}
}
public static class B extends A
{
@JsonProperty("secondary_key")
public final String secondaryKey;
@JsonCreator
B(@JsonProperty("primary_key") String primaryKey,
@JsonProperty("secondary_key") String secondaryKey)
{
super(primaryKey);
this.secondaryKey = secondaryKey;
}
@Override
public String toString() {
return "B{" +
"primaryKey='" + primaryKey + '\'' +
"secondaryKey='" + secondaryKey + '\'' +
'}';
}
}
public static class X
{
@JsonProperty("keys")
public final A keys;
@JsonCreator
X(@JsonProperty("keys") A keys)
{
this.keys = keys;
}
@Override
public String toString() {
return "X{" +
"keys=" + keys +
'}';
}
}
}
But you will have to create one more super class if you want to use default A deserializer or look here how you can solve this: https://stackoverflow.com/a/18405958/1032167