RegEx: Match everything up to the last space without including it

Question

I'd like to match everything in a string up to the last space but without including it. For the sake of example, I would like to match characters I put in bold:

RENATA T. GROCHAL

So far I have ^(.+\s)(.+) However, it matches the last space and I don't want it to. RegEx should work also for other languages than English, as mine does.

EDIT: I didn't mention that the second capturing group should not contain a space – it should be GROCHAL not GROCHAL with a space before it.

EDIT 2: My new RegEx based on what the two answers have provided is: ^((.+)(?=\s))\s(.+) and the RegEx used to replace the matches is \3, \1. It does the expected result:

GROCHAL, RENATa T.

Any improvements would be desirable.

How about matching `\S+` non-whitespaces before `$` end: [`(.+)\s(\S+)$`](https://regex101.com/r/kS5pF8/1) and replace with `$2, $1` similar @medvedev1088 solution with two groups `^(.+)\s(.+)` — bobble bubble, Mar 27 '16 at 15:00
@bobblebubble To me, your solution is much better than mine. — menteith, Mar 27 '16 at 16:19
I voted for medvedev1088's solution as my idea is very similar. — bobble bubble, Mar 27 '16 at 16:46
@bobblebubble Thanks. I also incorporated your idea in my response. — medvedev1088, Mar 27 '16 at 17:00

score 6 · Answer 1 · edited Mar 27 '16 at 13:13

6

Use a positive lookahead assertion:

^(.+)(?=\s)

Capturing group 1 will contain the match.

edited Mar 27 '16 at 13:13

Andrea Corbellini

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answered Mar 27 '16 at 12:55

James Buck

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medvedev1088 · Accepted Answer · 2016-03-27T16:57:15.397

5

^(.+)\s(.+)

with substitution string:

\2, \1

Update:

Another version that can collapse extra spaces between the 2 capturing groups:

^(.+?)\s+(\S+)$

edited Mar 27 '16 at 16:57

answered Mar 27 '16 at 12:55

medvedev1088

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y'd rather explain why he has to try it, and why it may solve his problem. – Muhammed Refaat Mar 27 '16 at 14:45

score -1 · Answer 3 · answered Mar 29 '16 at 07:56

-1

I like using named capturing groups:

rawName = RENATA T. GROCHAL
RegexMatch(rawName, "O)^(?P<firstName>.+)\s(?P<lastName>.+)", match)
MsgBox, % match.lastName ", " match.firstName

answered Mar 29 '16 at 07:56

Forivin

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RegEx: Match everything up to the last space without including it

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