How can I solve this variable issue?

Question

I know there are some questions like this , but none of the answers could solve my problem. So I'm gonna ask myself. How can I solve this problem? Sorry for don't specify more, I'm starting coding

score 0 · Answer 1 · answered Mar 18 '16 at 20:46

A way of solving the problem would be to make the variable score1 a field variable, so after the declaration of the java class make a variable with private visibility and then increment that variable.

 public class Test{
    private int score1;
    //Constructor for the class for setting the variable.
    public Test(){
    score1 = 0 //Whatever the start value should be
    }
  }

All in all you now have a variable which can be "seen" from the inner class of the actionlistener.

Hope that helps :)

score 0 · Answer 2 · answered Mar 18 '16 at 20:49

0

replace

int score1=sharedPreferences.getInt("score",DEFAULT);

with

final int score1=sharedPreferences.getInt("score",DEFAULT);

or instead you declare score as a class variable

public class someclass{
 int score1;
 //here comes the rest of the code
}

good luck

answered Mar 18 '16 at 20:49

Mohammed Elrashied

332
3
13

Didn't work. I declare it as public and the same problem continues. I can't define it as final because its a Preference – Arthur Moresche Mar 18 '16 at 21:54

score -1 · Answer 3 · answered Mar 18 '16 at 20:45

-1

Declare score1 as a class attribute.

answered Mar 18 '16 at 20:45

Birk

126
1
2
9

How can I solve this variable issue?

3 Answers3