split a string with the space bar

Question

The follow are my java code

i want to enter: asd 123456 hellohello

output:

asd

123456

hellohello

However it come out error. anyone can help me?

package test;

import java.util.Scanner;
public class test1 {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        Scanner sc = new Scanner (System.in);
        String cs = sc.next();

        String[] output = cs.split("\\s+");
        System.out.println(output[0]);
        System.out.println(output[1]);
        System.out.println(output[2]);
    }
}

Replace `sc.next();` with `sc.nextLine();` – user2004685 Mar 14 '16 at 07:21 — user2004685, Mar 14 '16 at 07:21
I have learn a new thing thank you – T Lam Mar 14 '16 at 07:40 — T Lam, Mar 14 '16 at 07:40

score 2 · Answer 1 · answered Mar 14 '16 at 07:31

There are a couple of things that I have fixed with your code:

import java.util.Scanner;
public class SplitStringWithSpace {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        String cs = sc.nextLine();
        //close the open resource for memory efficiency
        sc.close();
        System.out.println(cs);

        String[] output = cs.split("\\s+");
        for (String retval : output) {
            System.out.println(retval);
        }
    }
}

Use the enhanced for loop so you dont have to manually navigate the array.
Close the resource after you have used it.

@TLam You are most welcome! If the answer helped you, then please upvote it/pick as correct answer :) — Mukul Tripathi, Mar 14 '16 at 07:42

Ramanlfc · Answer 2 · 2016-03-14T07:25:24.590

0

next() only returns next token in the input not the entire line , your code will throw ArrayIndexOutOfBoundsException as it stands bcoz output has length equal to 1.

you need nextLine() method to get the entire line.

edited Mar 14 '16 at 07:25

answered Mar 14 '16 at 07:20

Ramanlfc

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Thank you i sole the question>~ – T Lam Mar 14 '16 at 07:40

score 0 · Answer 3 · answered Mar 14 '16 at 07:49

Here sc.next() uses spaces delimiter. So given the input as foo bar, you get:

sc.next(); //`foo`
sc.next(); //`bar`

Either you may go for sc.nextLint() and use rest of the code as it is. If you have to continue with sc.next(), you may try this code snippet.

while(sc.hasNext()) { //run until user press enter key
  System.out.println(sc.next());
}

split a string with the space bar

3 Answers3