How to use string formatting with specific nubmer of digits on hex Ascii

Question

In Python 2.7, I want to convert hex ascii number to itself using string formating with specific number of digits

Example:

hexNumber='9'
print '%02x' % (hexNumber)

Output:

score 1 · Accepted Answer · answered Mar 10 '16 at 19:59

1

You have a string, just zero-fill it to the desired width using str.zfill():

hexNumber.zfill(2)

The %x formatter is for integers only.

Demo:

>>> hexNumber = '9'
>>> hexNumber.zfill(2)
'09'

answered Mar 10 '16 at 19:59

Martijn Pieters

1,048,767
296
4,058
3,343

But the number of zeroes is not always the same. I may have need for 0 zeroes or even 4 zeroes. – Guy Markman Mar 11 '16 at 13:55
@GuyMarkman: leave that to the `str.zfill()` method. It'll add enough zeros to give you a string of the requested width. Note that I told it to pad out to 2 characters, but only 1 `0` was added. – Martijn Pieters Mar 11 '16 at 14:31
@GuyMarkman: for your *example* you'd never add 4 zeros, because you told the string formatter to pad out to 2 digits too. – Martijn Pieters Mar 11 '16 at 14:32

score 0 · Answer 2 · answered Mar 10 '16 at 20:07

0

You can also make use of Python's format command for string formatting. This allows you to specify a fill character, in this case 0 and a width as follows:

print "{:0>2s}".format('9')

This would display:

answered Mar 10 '16 at 20:07

Martin Evans

45,791
17
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score 0 · Answer 3 · answered Mar 10 '16 at 20:15

0

print(("{0:05X}".format(int("1C", 16))))

0001C

print(("{0:05X}".format(0x1C)))

0001C

answered Mar 10 '16 at 20:15

Hidan Jamanako

23
5

How to use string formatting with specific nubmer of digits on hex Ascii

3 Answers3