JS-regex, How can I make it to one replace() method?

Question

My goal is :

Delete all. except the numbers , but delete the zeros who before numbers 1 to 9

And I have this regex:

var validValue = inputValue.replace(/[^\d]/g, '').replace(/^0*/g, '');

But I want to make it in a one replace()

So how can I do that ?

I'm not sure you can. What's the issue of doing this in two steps? — Thomas Ayoub, Mar 10 '16 at 14:51
No problem, but I want it to be shorter, if its possible I do not know if it's possible — Moti Winkler, Mar 10 '16 at 14:53
Possible duplicate of [Regex to remove letters, symbols except numbers](http://stackoverflow.com/questions/6649327/regex-to-remove-letters-symbols-except-numbers) — Thomas Ayoub, Mar 10 '16 at 14:57

Wiktor Stribiżew · Accepted Answer · 2016-03-10T14:58:48.297

1

You want to remove all leading zeros and all non-digit symbols. It can be done with

/^0+|\D+/g

The regex matches

var re = /^0*|\D+/g; 
var str = '00567600ffg5566';
var result = str.replace(re, '');
document.body.innerHTML = str + " >>> " +  result;

edited Mar 10 '16 at 14:58

answered Mar 10 '16 at 14:56

Wiktor Stribiżew

Thank you ! Thank you also for the explanation! – Moti Winkler Mar 10 '16 at 14:58
2

@Thomas: [It works](https://regex101.com/r/fS1yC8/4). It removes the leading zeros and all non-digits inside the string. Moti, the `/g` in `/^0*/g` makes no sense since the start of string can only be matched once. Also, this regex may match an empty string, thus, it is best to replace the `*` with the `+` quantifier. – Wiktor Stribiżew Mar 10 '16 at 14:59

1 Answers1