C programming Strings printing

Question

I have a question on this string .

for example:

char ex1[20]="Hello hi";
int choose;
scanf("%d",&choose);

What should I do to make it print "hi" when user enters 1 and "hello" would be printed if he enters 0?

Thank you for your help.

Have you looked at using the strtok function to tokenize ex1 into two separate strings? — bruceg, Mar 09 '16 at 01:29
By defining the two words separately in an array. `char ex2 [2][20] = {"Hello", "hi"};` — Weather Vane, Mar 09 '16 at 01:32
@bruceg i dont how i can use strok because my array has more than 200 sentences and program goes line by line ask for position of the word if enter 1 then i would use strok to remove hi . — user4574134, Mar 09 '16 at 01:39

score 2 · Answer 1 · answered Mar 09 '16 at 03:06

2

The simplest solution would be:

if(choose == 1)
    printf("Hello\n");
else if(choose == 0)
    printf("hi\n");
else
    printf("Please enter 1 or 0.\n");

You don't need ex1 here.

answered Mar 09 '16 at 03:06

user253751

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score 1 · Accepted Answer · answered Mar 09 '16 at 03:56

I guess you want this.

#include<stdio.h>
#include<string.h>
void split(char*str, char** arr) {
    char* str2 = strstr(str, " ");
    *str2 = '\0';
    str2++;
    arr[0] = str;
    arr[1] = str2;
}
int main(void) {
    char ex1[20] = "Hello hi";

    char*arr[2];
    split(ex1, arr);

    int choose;
    scanf("%d", &choose);
    switch (choose) {
    case 0:
        puts(arr[0]);
        break;
    case 1:
        puts(arr[1]);
    }

    return 0;
}

The results are as follows

yes something like this but i have more than 200 lines but thank you i will use strstr function . — user4574134, Mar 09 '16 at 16:44

score 0 · Answer 3 · edited Mar 09 '16 at 01:35

0

Is this what you mean? I'm not sure exactly what you mean.

char buf[2];
fgets(buf, 2, stdin);
*buf == '1' ? puts("hi") : puts("hello");

This reads the first two characters from stdin, the standard input stream, and then prints "hi" if the first character is 1, or "hello" otherwise.

edited Mar 09 '16 at 01:35

Weather Vane

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answered Mar 09 '16 at 01:31

lost_in_the_source

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You have two `puts` and I prefer merging them: `puts(*buf == '1' ? "hi" : "hello");` – MikeCAT Mar 09 '16 at 01:35
This read the first one character (not two) because terminating null-character have to be stored in `buf`. – MikeCAT Mar 09 '16 at 01:36
`*buf == '1' ? puts("hi") : puts("hello");` - you should fire whoever writes code like this instead of using an `if` statement. – user253751 Mar 09 '16 at 03:27
Why? It's not like I'm nesting `? :` operators. @immibis – lost_in_the_source Mar 09 '16 at 22:57
@stackptr Because it's less readable than it could be easily. And in fact you put in *more work* to make it less readable! – user253751 Mar 09 '16 at 22:58
Was it you who downvoted? @immibis And how is it more work to use `? :` instead of `if else` – lost_in_the_source Mar 09 '16 at 23:00

C programming Strings printing

3 Answers3