nginx rewrite rule (convert segments to get paramters)

Question

I need

/secure/token/timestamp/path/to/the/resource/

to be rewritten in this format:

/s/path/to/the/resource/?st=token&e=timestamp

what I'm trying to do is:

location /secure/(?<token>)/(?<timestamp>)/(?<path>) {
    rewrite ^ /s/$path/?st=$token&e=$timestamp
}

but it's obviously not working. This syntax doesn't seemed to be correct. How can I play like this with urls in nginx rules?

EDIT: trying now something like this: the same result:

     location /secure/(.*)/(.*)/(.*) {
         rewrite ^ /s/$3?st=$1token&e=$2timestamp;
    }

score 1 · Accepted Answer · answered Mar 07 '16 at 17:53

1

You have multiple problems. You have confused prefix locations with regex locations. Your named captures do not contain any content. And your numeric captures are probably too broad.

See this for location syntax.

You should probably use a prefix location, then capture in the rewrite:

location /secure/ {
    rewrite ^/secure/([^/]*)/([^/]*)/(.*)$ /s/$3?st=$1&e=$2 last;
}

answered Mar 07 '16 at 17:53

Richard Smith

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Hi Richard, How we can do the same thing in opposite way. I want to convert get parameters to segments? – Akshay Deshmukh Oct 03 '19 at 10:41
@AkshayDeshmukh see [this answer](https://stackoverflow.com/questions/54329332/nginx-redirect-url-with-query-strings/54330947#54330947). – Richard Smith Oct 03 '19 at 10:49

nginx rewrite rule (convert segments to get paramters)

1 Answers1