Setting strtotime adding a variable to amount of days

Question

I am trying to export a certain number of days and setting it to the variable $max_future. Currently it is a set amount of days but I want the users input variable to be the number it has instead.

Currently it is set as:

$max_future = date("Y-m-d", strtotime($today . "+6 days"));

I want something like:

$exportDays = '9'; //(or whatever the user input was)
$max_future = date("Y-m-d", strtotime($today . "+$exportDays days"));

Is this possible? I appreciate any help

Have you tried it before posting question ? – Armen Mar 02 '16 at 17:25 — Armen, Mar 02 '16 at 17:25

score 1 · Accepted Answer · answered Mar 02 '16 at 17:30

1

Try:

$max_future = date("Y-m-d", strtotime($today . "+" . $exportDays . " days"));

answered Mar 02 '16 at 17:30

SScotti

2,158
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This worked, thanks! I should have thought of doing this... still learning :) – Mar 02 '16 at 18:52

score 0 · Answer 2 · answered Mar 02 '16 at 17:30

0

Something like this :

<?php
$output = 9; // you can take this value from input.
$today = date("Y-m-d");
echo date('Y-m-d', strtotime($today. ' +'.$output. ' days'));
?>

answered Mar 02 '16 at 17:30

Drudge Rajen

7,584
4
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43

score 0 · Answer 3 · answered Mar 02 '16 at 17:34

0

<?php
    $exportDays = $_REQUEST['exportDays']; // or however you want to get it from user input
    $max_date = date('Y-m-d', strtotime(date('Y-m-d') . ' +' . $exportDays . ' days'));

answered Mar 02 '16 at 17:34

Davis

856
4
11

Setting strtotime adding a variable to amount of days

3 Answers3