R: abc<-c(1:15) vs abcd<-1:15

Question

What is the difference between the following commands:

abc <- 1:15
abcd <- c(1:15)
abc
abcd

The output is:

> abc <- 1:15
> abcd <- c(1:15)
> abc
 [1]  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15
> abcd
 [1]  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15

No difference. Just unnecessary additional `c()` in your second attempt. Just read the manual please. — David Arenburg, Feb 26 '16 at 11:16
You can use `identical(abc, abcd)` in such cases to check if both are _exactly_ equal — talat, Feb 26 '16 at 11:21

score 3 · Accepted Answer · answered Feb 26 '16 at 11:17

3

c() is a function to concatenate vectors. In your example you only supply one vector - 1:15 so they are functionally the same.
You need c() if you want to concatenate two or more ranges, for example to not have 13 in your vector: c(1:12, 14:15)

answered Feb 26 '16 at 11:17

Robin Gertenbach

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R: abc<-c(1:15) vs abcd<-1:15

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