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I have a situation where two different webservice methods should return exactly the same XML file.

Right now when I get those two responses I compare those XML files using XMLUnit framework which shows xpath location + differences in various nodes like in the following code:

XMLUnit.setIgnoreWhitespace(true);
DetailedDiff diff = new DetailedDiff(XMLUnit.compareXML(firstXML,secondXML));
List<Difference> allDiifferences= diff.getAllDifferences();

for(Difference difference : allDiifferences){
    System.out.println(difference.getControlNodeDetail().getXpathLocation()+" ("+difference.getControlNodeDetail().getValue()+") /("+difference.getTestNodeDetail().getValue()+")");
}

When I am running the tests in SoapUI I use 

log.info
log.error

methods to show the differences which are storred in XMLs.

Is there any better way to show those differences?

ParkerHalo
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JMK
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  • You need to explain "better" means for you! – SiKing Feb 26 '16 at 16:47
  • @SiKing my goal is to find a better solution for showing the differences than logging this to the SoapUI's console. I was asking about this because I wrote a code for manual testers who use SoapUI and they do not like to use its console. Thus I asked about any different approach. – JMK Feb 27 '16 at 19:10

2 Answers2

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I have done some R&D about this and this is what i can tell you, to the best of my knowdledge. XMLUnit offers the most stable and lightweight tools that can effectively find a variety of differences between two xml files. Ofcourse you have the liberty of choosing how to show these differences once they are found.

SoorajSethumadhavan
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XMLUnit is good for your use case. or you can try alternative approach of using JAXB to convert XML to Java Objects and then write your custom comparators. (JAXB tools can auto generate classes from your DTDs)

Anil
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