Parsing a blank / whitespace with RegexParsers

Question

What is the problem with parsing the blank/whitespace?

scala> object BlankParser extends RegexParsers {
         def blank: Parser[Any] = " "
         def foo: Parser[Any] = "foo"
       }
defined module BlankParser

scala> BlankParser.parseAll(BlankParser.foo, "foo")
res15: BlankParser.ParseResult[Any] = [1.4] parsed: foo

scala> BlankParser.parseAll(BlankParser.blank, " ")
res16: BlankParser.ParseResult[Any] =
[1.2] failure: ` ' expected but ` ' found


 ^

scala>

score 4 · Accepted Answer · edited May 23 '17 at 12:19

4

the lexer for scala throws blankspaces away. try override val skipWhitespace = false to avoid this.

the question was already solved so it seems... Scala parser combinators for language embedded in html or text (like php)

edited May 23 '17 at 12:19

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answered Aug 25 '10 at 08:48

tarrasch

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Parsing a blank / whitespace with RegexParsers

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