PHP remove first zeros

Question

Want to remove all 0 placed at the beginning of some variable.

Some options:

if $var = 0002, we should strip first 000 ($var = 2)
if var = 0203410 we should remove first 0 ($var = 203410)
if var = 20000 - do nothing ($var = 20000)

What is the solution?

drAlberT · Accepted Answer · 2023-06-14T09:04:48.163

89

Just cast it to integer

$var = (int)$var;

edited Jun 14 '23 at 09:04

answered Aug 25 '10 at 07:35

drAlberT

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2

@Lekensteyn: Only if it is meant to be a statement instead of an expression. – Gumbo Aug 25 '10 at 07:39
it was not the entire line :) ehehhe – drAlberT Aug 25 '10 at 07:40
is there similar function in javascript? – James Aug 25 '10 at 07:41
of course, casting is a feature present in almost every language. In JS you can use parseInt() – drAlberT Aug 25 '10 at 07:42
(int)$var is an statement, but assigning it to $var looks like a expression to me. Anyway, this is a oneliner, you don't need to add something else after it. – Lekensteyn Aug 25 '10 at 07:43
2

@Workinghard, `parseInt(var, 10)` or `1 * var` (my favorite :)) – Lekensteyn Aug 25 '10 at 07:44
@Lekensteyn: `(int)$var` is an expression and an assignment is an expression too. – Gumbo Aug 26 '10 at 07:55
Just remember if you do it this way (int)$var, and the number is above max integer, 2147483647 - then your number will change and not only remove the zero – WoodyDRN Dec 02 '15 at 10:31
When I tried this solution in php version 5.3.3 and not working as expected. I tried with $var = 0131;$var = (int)$var);echo $var; it results 89. – Viswa Aug 26 '16 at 13:32
@viswa Google for "89 to octal" – drAlberT Aug 28 '16 at 13:25
Of course it is an I interpreter behaviour to treat a number starting g with 0 as an octal representation of an integer .. I think the "printed number" in the question was in fact it's striking g representation .. maybe it cab be investigated deeper – drAlberT Aug 28 '16 at 13:31
@drAlberT So what is the point my value got changed and if I try to get a value from an array using this value as key then, I will get an in-appropriate result or empty result. – Viswa Aug 29 '16 at 07:53
I really think the "pseudo code" in the question was referring to *strings* .. an octal number IS already an int .. the representation is not influent on the value. Your test should be on `$var = '0131';`, a string. – drAlberT Aug 29 '16 at 09:00
Watch your step. That only works for integers! If the value is a decimal number, then the decimal is removed. Therefore, I think ltrim is the better idea to remove leading zeros (as the title of the question is) – Sarah Trees Nov 22 '19 at 09:53
true, but the question was for integers ;) – drAlberT Nov 22 '19 at 10:30

score 35 · Answer 2 · answered Aug 25 '10 at 07:35

35

Maybe ltrim?

$var = ltrim($var, '0');

answered Aug 25 '10 at 07:35

robertbasic

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Yes, this way we don't affect possible decimal places. – Sarah Trees Nov 22 '19 at 09:54

score 15 · Answer 3 · answered Aug 25 '10 at 07:36

15

$var = ltrim($var, '0');

This only works on strings, numbers starting with a 0 will be interpreted as octal numbers, multiple zero's are ignored.

answered Aug 25 '10 at 07:36

Lekensteyn

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score 5 · Answer 4 · answered Jun 15 '14 at 18:05

5

Just use + inside variables:

echo +$var;

answered Jun 15 '14 at 18:05

poostchi

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Interesting. Can you post a link to the relevant documentation? – brasofilo Jun 15 '14 at 18:36
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Really I have no reference! but works like a charm! change strings to numbers and remove all unnecessary zero and change string to number. – poostchi Jun 15 '14 at 18:44
1

A + unary operator acts on numbers, so you are doing an implicit cast ... bad code as it hides the logic with no other advantages IMHO ... – drAlberT Jan 05 '17 at 23:30
Nice try, it work in Javascript but with PHP, you just cast the var :-D – benftwc May 31 '18 at 13:25
loll... I like your reply @poostchi. it works like a charm indeed. I just used it in my project. but the fact that there's no relevant documentation got me thinking :( – Sam Banana Feb 12 '21 at 20:14
2

Documentation : it is called "identity" → https://www.php.net/manual/en/language.operators.arithmetic.php – Jose Manuel Abarca Rodríguez May 05 '21 at 16:40

score 5 · Answer 5 · answered Aug 25 '10 at 07:35

5

$var = strval(intval($var));

or if you don't care about it remaining a string, just convert to int and leave it at that.

answered Aug 25 '10 at 07:35

Amber

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score 2 · Answer 6 · answered May 04 '18 at 13:41

2

Carefull on the casting type;

var_dump([
    '0014010011071152',
    '0014010011071152'*1,
    (int)'0014010011071152',
    intval('0014010011071152')
]);

Prints:

array(4) {
    [0]=> string(16) "0014010011071152"
    [1]=> float(14010011071152)
    [2]=> int(2147483647)
    [3]=> int(2147483647)
}

answered May 04 '18 at 13:41

Martijn Hoogstraten

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for [2]=> int(2147483647) [3]=> int(2147483647) its integer overflow , so results will not be expected if value is more than max integer limit i.e. 2,147,483,647 (or hexadecimal 7FFFFFFF16) – Asad kamran Jun 07 '23 at 11:20

Jhourlad Estrella · Answer 7 · 2022-01-31T11:49:40.700

2

Multiply it by 1

$var = "0000000000010";
print $var * 1;  

//prints 10

edited Jan 31 '22 at 11:49

answered Jul 20 '18 at 08:14

Jhourlad Estrella

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PHP remove first zeros

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