DownLoad Shippo label through controller

Question

After filling necessary package info, I manage to create a responsed Transaction object through goShippo API call: Transaction.create(Map, apiKey). Form the responsed Transaction object, I can get the shipping label as a Url: transaction.getObjectId().

The problem that I have is how can I enable my client to download the shipping label.

My current code is:

fileName= "https://shippo-delivery-east.s3.amazonaws.com/b1b0e6af.pdf?xxxxxx";

File file = new File(fileName);
String mineType = URLConnection.guessContentTypeFromName(file.getName());
    if(mineType == null) {
        System.out.println("mineType is not detectable");
        mineType = "application/octet-stream";
    }

    response.setContentType(mineType);
    response.setHeader("Content-Disposition"
            , String.format("inline; filename=\"" + file.getName() +"\""));


    response.setContentLength((int)file.length());

    InputStream inputStream = new BufferedInputStream(new FileInputStream(file));

    FileCopyUtils.copy(inputStream, response.getOutputStream());

The error that I have is that the file is not found, but when I pass the fileName on browser, I can see the shipping label.

score 1 · Accepted Answer · answered Feb 29 '16 at 06:15

The documentation says:

After you've successfully created a URL, you can call the URL's openStream() method to get a stream from which you can read the contents of the URL. The openStream() method returns a java.io.InputStream object, so reading from a URL is as easy as reading from an input stream.

So you need to create a URL object and from it you can get the inputStream.

It looks like this:

import java.io.BufferedInputStream;
import java.io.InputStream;
import java.net.URL;

String fileName= "https://shippo-delivery-east.s3.amazonaws.com/b1b0e6af.pdf?xxxxxx";

URL urlToLabel = new URL(fileName);

InputStream inputStream = new BufferedInputStream(urlToLabel.openStream());

DownLoad Shippo label through controller

1 Answers1