Parceling a HashMap that has an array of strings

Question

I have the following object:

public class HolderLanguageText implements Parceable { 
    final private HashMap<Integer, String[]> mapText;

    public HolderLanguagetext(Parcel in) { 
         mapText = new HashMap<Integer, String[]>();
         in.readMap(mapText, ???)

    }

    public static final Parcelable.Creator<HolderLanguageText> CREATOR
        = new Parcelable.Creator<HolderLanguageText>() {

       public HolderLanguageText createFromParcel(Parcel in) {
           return new HolderLanguageText(in);
       }

       public HolderLanguageText[] newArray(int size) {
           return new HolderLanguageText[size];
       }
    };


}

What do I put in the line in.readMap(mapText, ???)? I know it's something like String.class.getClassLoader(), but this is an array.

Care to explain why? `{"value" : ["string1", "string2"]}` seems much more serializable to me than a HashMap — OneCricketeer, Feb 18 '16 at 16:44
@cricket_007 This is legacy code that will break in many places if I do that. — Kristy Welsh, Feb 18 '16 at 16:45
How will anything break? You serialize and deserialize in the same class. — OneCricketeer, Feb 18 '16 at 16:46
I don't mean change the HashMap to JSONObject in the `HolderLanguageText` class. Only convert the HashMap when you need to store it in the Parcel (which is simply `new JSONObject(mapText)`) , then read out the JSON in the un-parcel and store it back into the HashMap. — OneCricketeer, Feb 18 '16 at 16:49

score 0 · Answer 1 · edited Feb 18 '16 at 16:27

0

Did you tried this in place of ????

Class.forName("[Ljava.lang.String;");

edited Feb 18 '16 at 16:27

Andrey E

856
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answered Feb 18 '16 at 15:58

Phanindra Gopishetty

161
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Or just try class.forName("String[]") – Phanindra Gopishetty Feb 18 '16 at 16:06

Parceling a HashMap that has an array of strings

1 Answers1