StackOverFlowError in Java code

Question

I am writing a simple code and I am receiving an StackOverflowError in following code at line 2: Tmp4 t = new Tmp4 (); I dont get error if I omit line 6 ( initialization of p) or on omiting line 2. Also I am not doing a recursive call.

I want to ask why it is giving a such Error. And on omitting line 2 or line 6 it is not giving StackOverflowError.

Also it gives on my system only or problem with the code.

Thanks.

public class Tmp4 {
    Tmp4 t = new Tmp4 ();

    public static void main(String[] args) {
            System.out.println("main");
            Tmp4 p = new Tmp4 ();
            System.out.println("main2");

    }
}

user2004685 · Answer 1 · 2016-02-16T16:55:00.820

1

By doing Tmp4 t = new Tmp4 (); you are trying to initialize the object of the same class within it's object which is going in infinite recursion and giving you StackOverflow Exception.

Remove this line as shown below:

public class Tmp4 {
    /* Remove this line */
    Tmp4 t = new Tmp4 ();

    public static void main(String[] args) {
        System.out.println("main");
        Tmp4 p = new Tmp4 ();
        System.out.println("main2");
    }
}

edited Feb 16 '16 at 16:55

answered Feb 16 '16 at 16:52

user2004685

9,548
5
37
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Cant I initialize an object in another Object in Java? – IDontKnow006 Feb 16 '16 at 16:53
Yes. But in this case it is going in infinite recursion and hence you are getting StackOverflow Exception. – user2004685 Feb 16 '16 at 16:55
Can u explain it in a bit detail – IDontKnow006 Feb 16 '16 at 17:00
Sure. What are you trying to achieve? – user2004685 Feb 16 '16 at 17:01

score 1 · Answer 2 · answered Feb 16 '16 at 17:01

1

StackOverFlowError happens when you have an infinite loop in your code just like you have it in line 2.

public class Tmp4 {
Tmp4 t = new Tmp4 (); // This creates an infinite loop
}

That line 2 is called instance initializer and it happens even before the constructor. Now, since you are creating another instance of Tmp4, it will then call it's own instance initializers which will call theirs and so on. The loop will never end.

answered Feb 16 '16 at 17:01

Bozo Tegeltija

33
7

Thanks Bozo for brief explanation. – IDontKnow006 Feb 16 '16 at 17:09

MMike · Accepted Answer · 2016-02-16T18:05:35.473

0

public class Tmp4 {
    Tmp4 t = new Tmp4 (); //Line 4

public static void main(String[] args) {
    System.out.println("main"); // Line 1
    Tmp4 p = new Tmp4 (); //Line 2
    System.out.println("main2"); //Line 3

    }
}

When you start your program, line1 and 2 are the first executed. line 2 is where you initialise a new object of type Tmp4. With initialisation line 4 gets called which creates again a new object of type Tmp4. With initialisation of t line 4 gets called again resulting in an infinite recursive call, hence the StackOverflowException. Remove line 4 to remove the cause of the StackOverflowException. Because of the infinite loop caused by line 4, line 3 is never executed.

edited Feb 16 '16 at 18:05

answered Feb 16 '16 at 16:57

MMike

598
3
23

It is like calling to itself again and again (uncontrolled recursion) ? – IDontKnow006 Feb 16 '16 at 17:07
@IDontKnow006 yes, line 4 causes itself to get called again and again. You are welcome. :) – MMike Feb 16 '16 at 18:02

StackOverFlowError in Java code

3 Answers3