So I am creating a simple password program that asks you for an input but masks it with asterisks (*). The code I have works, but when I backspace the string returned is like I had never backspaced.
What I would Type:
12345
I would hit the backspace twice, and the string would look like this:
123
But when I hit enter, it returns this:
1234
Here is the code that I have.
#include <iostream>
#include <string>
#include <conio.h> //Regular includes.
using namespace std;
string Encrypted_Text(int a) { //Code for the password masker
string Pwd = " "; //Creates password variable.
char Temp; //Temporary variable that stores current keystroke.
int Length = 0; //Controls how long that password is.
for (;;) { //Loops until the password is above the min. amount.
Temp = _getch(); //Gets keystroke.
while (Temp != 13) { //Loops until enter is hit.
Length++; //Increases length of password.
Pwd.push_back(Temp); //Adds newly typed key on to the string.
cout << "*";
Temp = _getch(); // VV This is were the error is VV
if (Temp == 8) { // detects when you hit the backspace key.
Pwd.pop_back; //removes the last character on string.
cout << "\b "; //Deletes the last character on console.
Length--; //decreases the length of the string.
}
}
if (Length < a) { //Tests to see if the password is long enough.
cout << "\nInput Is To Short.\n";
Pwd = "";
Temp = 0;
Length = 0;
}
else {
break;
}
}
return Pwd; //Returns password.
}
And in my main function i have this:
string Test = Encrypted_Text(5);
cout << "you entered : " << Test;
