Consider the following code:
#include<utility>
struct S {
void f(int) = delete;
void f(int) && { }
};
int main() { }
It doesn't compile saying that the member method cannot be overloaded and it makes sense, of course.
On the other side, the following code compiles:
#include<utility>
struct S {
void f(int) & = delete;
void f(int) && { }
};
int main() {
S s;
// s.f(42); <-- error, deleted member method
std::move(s).f(42);
}
Is that legal code?
Wouldn't it be possible to define two completely different interfaces within the same class, the former to be used with lvalues, the latter with rvalues?
Apart from the fact that it doesn't make much sense, but it really hurts me.
Shouldn't a deleted function be deleted as a whole, instead of deleted only if you are a lvalue?
Which is the purpose of this feature? Is it the classic obscure corner case or is there something more I can't see?